(x+2)^2-10=(x+3)(x+2)-4

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Solution for (x+2)^2-10=(x+3)(x+2)-4 equation: 



(x+2)^2-10=(x+3)(x+2)-4

We move all terms to the left:

(x+2)^2-10-((x+3)(x+2)-4)=0

We multiply parentheses ..

-((+x^2+2x+3x+6)-4)+(x+2)^2-10=0



We calculate terms in parentheses: -((+x^2+2x+3x+6)-4), so:

(+x^2+2x+3x+6)-4

We get rid of parentheses

x^2+2x+3x+6-4

We add all the numbers together, and all the variables

x^2+5x+2

Back to the equation:

-(x^2+5x+2)



We get rid of parentheses

-x^2-5x+(x+2)^2-2-10=0

We add all the numbers together, and all the variables

-1x^2-5x+(x+2)^2-12=0

We move all terms containing x to the left, all other terms to the right

-1x^2-5x+(x+2)^2=12

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